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CGP EDU Academic Team
Published on: September 12, 2026
A wave is given by $y = 3 \sin 2 \pi \left(\frac{t}{0.04} - \frac{x}{0.01}\right)$ , where y is in cm. Frequency of wave and maximum acceleration of particle will be
Text Solution
Verified by ExpertsThe correct answer is:
D
Comparing the given equation with standard equation $y = a \sin 2 \pi \left(\frac{t}{T} - \frac{x}{\lambda}\right)$
⇒ ⇒ T = 0.04 sec ⇒ ⇒ $\nu = \frac{1}{T} = 25 \mathrm{Hz}$
Also $(A)_{\text{max}} = \omega^2 a = \left(\frac{2 \pi}{T}\right)^2 \times a = \left(\frac{2 \pi}{0.04}\right)^2 \times 3$
=7.4 × × 10 4 cm/sec 2 .
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